Line ab is parallel to CD and line PQ is transversal measure of one angle is given find the measure of the following angles
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(i) 75°.
(ii) 75°.
(iii) 105°.
(iv) 75°.
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Given that AB||CD and PQ is the transversal.
Now,
Angle BRT = 105 degrees
Now,
Angle ART = 180 - Angle BRT
(since, they are linear pair)
Thus,
Angle ART = 180-105 = 75 degrees
Angle CTQ = Angle ART
(since, they are corresponding Angles)
Thus,
Angle CTQ = 75 degrees
Also,
Angle DTQ = Angle BRT
(since, They are corresponding Angles)
Thus,
Angle DTQ =105 degrees
Again,
Angle PRB = Angle ART
(since, They are vertically Opposite Angles)
Thus,
Angle PRB = 75 degrees
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