Question

Line AXB is parallel to line MYN. Angle BXY = 2h - 30 and angle XYN = 4h + 60.
Calculate h.
Calculate angle XYM.

Would appreciate the help,

Thanks. :)

Answer 1

X+Y=180---interior angles
2n-30+4n+60=180
6n+30=180
150=6n
n=25

angle XYM=angleYXB---alternate angles
XYM=2n-30
XYM=2(25)-30---n=25
XYM=50-30
XYM=20
hope it helps...
plz mark brainliest...