Line PQ is parallel to line RS where points P,Q,R and S have co-ordinates (2, 4), (3, 6), (3, 1) and (5, k) respectively. Find value of k.
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line PQ || line RS ------(given)---- (1)
By using slope formula:
slope of line PQ= y2-y1÷x2-x1
=6-4÷3-2
=2
Now,
slope of line RS= y4-y3÷x4-x3
=k-1÷5-3
=k-2÷2
line PQ|| line RS ------from (1)
line PQ= Line RS
k-2÷2=2
k-2 =2+2
k-2=4
k=6
value of k is 6
By using slope formula:
slope of line PQ= y2-y1÷x2-x1
=6-4÷3-2
=2
Now,
slope of line RS= y4-y3÷x4-x3
=k-1÷5-3
=k-2÷2
line PQ|| line RS ------from (1)
line PQ= Line RS
k-2÷2=2
k-2 =2+2
k-2=4
k=6
value of k is 6
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