Question

line PQ is parallel to y-axis and passing through the point (-4,3) Write the equation of the line PQ​

Answer 1

Given : line PQ is parallel to y-axis and passing through the point (-4,3)

To Find : equation of the line PQ​

Solution:

PQ is parallel to y-axis and passing through the point (-4,3)

PQ is parallel to y-axis  => slope = 1/0

passing through point ( - 4 , 3)

Equation of the line PQ

y - 3 = (1/0) (x - (-4))

=> 0. ( y - 3) = 1 ( x + 4)

=> 0 = x + 4

=> x + 4 = 0

x + 4 = 0   is the equation of the line PQ

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