Question

line “r” is perpendicular to the line 3y = 6x + 9. Find the gradient of the line “r”

Answer 1

Given:

Line:

$\to \bold{3y = 6x + 9}$

To find:

The gradient of the line “r”=?

Solution:

Formula:

$y = mx +c$

$m \times n = -1$

Solve the given value:

$\to \bold{3y = 6x + 9}$

$\to 3y = 3(2x + 3)\\\\\to y = \frac{3(2x + 3)}{3}\\\\\to y = (2x + 3)$

compare the value with the $y = mx +c$:

$\to m= 2 \\\\\to c=3$

The gradient of the line (m) = 2

The gradient of the line perpendicular (n)= $- \frac{1}{2}$

$\to 2 \times \frac{-1}{2} \\\\\to -1$

The final value is "-1".