Question

line segment AB is parallel to another line- segment CD .O is the mid point of AD show that .
(1) triangle AOB = triangle DOC
(2) O is also mid - point of BC
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Answer 1

Answer:

See below:

Step-by-step explanation:

In triangle AOB and DOC,

angle OAB =angle ODC (alternate angles on perpendicular lines)

AO=DO (O is the midpoint of AD)

angle AOB= angle DOC (vertically opposite angles)

Therefore,AOB is congruent to DOC BY ASA rule

Therefore,BO=CO (cpct)

Therefore, O is mid point of BC

Answer 2

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Hopr it helps....!!