Question

linear equation chapter question number 2 and 3 can any one help me out of this​

Answer 1

Step-by-step explanation:

2) Let the number be x.

x/2 + 3/4x =25/2

5/4x = 25/2

x=10

So the number is 10.

3)Let the consecutive multiples be 3(x-1), 3x and 3(x+1)

3(x-1) + 3x + 3(x+1)= 126

3x-3+3x+3x+3=126

9x=126

x=14

The consecutive multiples are 3*(14-1), 3*14, 3*(14+1)

that is 39, 42 and 45.

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Hope you got everything clearly.