Question

Linear Equation
Find the point where the graph of linear Equation 2x + 3y = 6 intersects y-axis.
Wrong or irrelevant questions will be reported.​

Answer 1

2x+3y=6

Since , the line intersects at y−axis.

Put x=0 in the given equation

⇒y=2

Hence, the line intersects y−axis at (0,2)

Answer 2

The point is P(0, 2).

$taking \: the \: point \: on \: which \: the \: \\ line \: intersects \: the \: y \: axis \\ p(0.y) \: \\ we \: have \: value \: of \: x \: substituting \: \\ 2x + 3y = 6 \\ 2(0) + 3y = 6 \\ 0 + 3y = 6 \\ 3y = 6 \\ y = \frac{6}{2} \\ y = 2 \\ hence \: the \: point \: will \: be \: p(0.2)$

*please take "." as a comma..

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