Question

Linear Equations
Exercise 2.2


Question 11: Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?

Answer 1

Let Baichung’s age be x

Then,
His father will be (x+29)
His grandfather will be (x+26+29)

ATQ,
x+x+29+x+29+26=135
3x+84=135
3x=51
x=51/3
x=17

THUS,
Baichung’s is 17 yrs old
Baichung’s father is (x+29)=46 yrs old
Baichung’s grandfather is (x+29+26)=72 yrs old


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Answer 2

Answer :

Baichung's age = 17 years.

Baichung's fathers age = 46 years.

Baichung's grandfather's age = 72 years.

Step-by-step explanation :

Let the age of Baichung be x years.

Age of his father = x + 29 years.

Age of his grandfather = x + 29 + 26 = x + 55 years.

According to the question ;

x + x + 29 + x + 55 = 135

⇒ 3x + 84 = 135

⇒ 3x = 135 - 84

⇒ 3x = 51

⇒ x = 51 / 3

⇒ x = 17

Hence,

Baichung's age = 17 years.

Baichung's fathers age = 46 years.

Baichung's grandfather's age = 72 years.