Linear Equations
Exercise 2.2
Question 6: Three consecutive integers add up to 51. What are these integers?
Answers
Answered by
3
Let the three consecutive integers to be x , x + 1 and x + 2
x + x + 1 + x + 2 = 51
3x + 3 = 51
3x = 48
x = 48/3
x = 16
So, rest of the numbers are 16,17 and 18
Hope it helps !
x + x + 1 + x + 2 = 51
3x + 3 = 51
3x = 48
x = 48/3
x = 16
So, rest of the numbers are 16,17 and 18
Hope it helps !
Answered by
1
Hello !
Let the three consecutive integers be x , x + 1 and x + 2
Given :-
x + x + 1 + x + 2 = 51
3x + 3 = 51
3x =51 - 3
3x = 48
x = 48/3
x = 16
-------------------------------------------------
The no:s are 16 , 17 , 18
Let the three consecutive integers be x , x + 1 and x + 2
Given :-
x + x + 1 + x + 2 = 51
3x + 3 = 51
3x =51 - 3
3x = 48
x = 48/3
x = 16
-------------------------------------------------
The no:s are 16 , 17 , 18
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