Linear Equations
Exercise 2.2
Question 7: The sum of three consecutive multiples of 8 is 888. Find the multiples.
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let the multiples be x,x+8,x+16
according to the problem,
x+(x+8)+(x+16)=888
3x+24=888
3x = 864
x=288
therefore the multiples are 288,296,304
according to the problem,
x+(x+8)+(x+16)=888
3x+24=888
3x = 864
x=288
therefore the multiples are 288,296,304
Answered by
0
Hope it helps you....
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