lines LM and PN intersect at point O. POM = 110° degree find the remaining angles.
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Answer:
✨Heya mate!!✨
Step-by-step explanation:
∆C+∆D=180° (sum of co-interior angle=180°)
∆D=180-110=70°
∆B=∆D (opposite angles of ll gm)
∆B=70°
∆A= 110° ∆B=70° ∆D=70°
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Please see the attached picture ; )
remember: Vertical angles are EQUAL!!!!!
Vertical angles are angles that are opposite to each other.
∠POM = 110°
∠POM and ∠LON are VERTICAL ANGLES, so they are equal.
⇒ ∠LON = 110°
To find ∠POL and ∠MON we add the two KNOWN angles and subtract them to 360(the equal of all angles/circle)
= 360 - (∠POM + ∠LON)
= 360 - (110 + 110)
= 360 - 220
= 140°
so the total angle of two unknown angles is 140°.
∠POL and ∠MON are VERTICAL ANGLES!, so they are congruent or the same.
140 / 2 = 70°
Answer:
∠POM = 110°
∠LON = 110°
∠POL = 70°
∠MON = 70°
HOPE IT HELPS ;)
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