Lisa and paul started a journey of distance 360km. if lisa and paul travel at the speed of 40 kmph and 60 kmph respectively. how many minutes early can paul reach the destination?
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wrong subject ........ sorry
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The equation to ascertain the speed or the connection between the blend of speed, separation and time is that the speed is equivalent to remove isolated. Here we have two of the parts for example the separate voyage and the speed and we need to make sense of the time taken by both Lisa and Paul separately, so-
S = D/T
Lisa's speed = 40 kmh (S1)
Paul's speed = 60 kmh (S2)
Distance = 360km
So, for Lisa:
S1 = D/T1
40 = 360/T1
T1 = 360/40 = 9 hrs
For Paul:
S2 = D/T2
60 = 360/T2
T2 = 360/60
T2 = 6 hrs
So Paul reaches 3 hours i.e., 180 minutes before Lisa."
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