Political Science, asked by priyankaaaa1100, 6 months ago

list of nonpartisan countries

Answers

Answered by Anonymous

15

Answer:

Bahrain – Political "parties" are banned, but political "societies" are allowed. ...

Kuwait – Political "parties" are not legally recognized, but political blocs are allowed. ...

Qatar – Political parties are banned.

Oman – Political parties are banned.

Saudi Arabia – Political parties are banned.

Previous Question

Next Question

Similar questions

Biology, 3 months ago

write the procedure to obsteve the dermal tissue of leaf (rhoe or Betel plant) .Draw the labelled diagram and answer the given questions...

History, 3 months ago

Discuss what you like most and what you like least about the climate in your country. Give reasons for your answers using adverbs of degree.

Math, 3 months ago

1 A number is of the form -q/2. Given that it is a whole number, an integer and a rational number, which of these is true? a) q<0 and the digit in the unit place of q is 2, 4, 6, 8, 0. b) 90 and the digit in the unit place of q is 2, 4, 6, 8, 0. c) q<0 and the digit in the unit place of q is 1, 3, 5, 7, 9. d) q>0 and the digit in the unit place of q is 1, 3 , 5, 7, 9.

English, 6 months ago

हाउ डिड द नेचर एंड हिस फैमिली मेंबर्स व्हेन द फर्स्ट डे ऑफ द जर्नी...

Math, 6 months ago

1. Find three rational numbers between -5/6 and3/8...

Social Sciences, 10 months ago

XRANTY LEVEL 2 Give Reasons for the following The iron and steel indust no Iron and stool Industry is considered as the basic indum The textile mills were initially locate Hills were initially located in Maharashtra and Gujarat hlormation technology Industry is the knowledge-based The development of industries helps in the growth or ustries helps in the growth of human life. Very Short Answer at...

Science, 10 months ago

a can be used to produce heat energy at a reasonable cost is known as...

Math, 10 months ago

Prove the following identities: $\frac{1}{ \sec \alpha + \tan \alpha } - \frac{1}{ \cos\alpha } = \frac{1}{ \cos \alpha } - \frac{1}{ \sec\alpha - \tan\alpha }$ ...