Question

List the potential solutions to 2 ln x = 4 ln 2 from least to greatest.

Answer 1

Given:

x= 4

To prove:

Find least and greatest value.

Solution:

$\Rightarrow b^{a}$....(i)

taking log in equation.

$\Rightarrow \ln \ b^{a} \\\\ \Rightarrow a \times \ln b$

where ln is natural log.

$\ x =\ 4$

square the above equation and take a log.

$\Rightarrow x^2 = 4^2 ....(a)\\\\\ take \log : \log x^2 = \log 4^2 \\\\\Rightarrow 2 \log x = 2 \log 4$

After solving above equation the value of x is = $\pm 4$

OR

remove squares of equation a, it will give:  $\pm 4$

The least and greatest value is=  -4 and +4.

Answer 2

Answer:

-4 , 4

Is the answer