Question

(lll) solve
$(a) \: 2 \: (3x + 5) = 4$
$(b) \: \frac{x}{3} + \frac{x}{4} = 5$
$(c) \: \frac{x}{3} + 7 = \frac{x}{2} + 5$

Answer 1

a)x=(-1)
b)x=(60/7)
c)x=12

Answer 2

(a) 2(3x + 5) = 4
= 6x + 10 = 4
6x = 4 - 10
6x = - 6
x = - 6 / 6
x = - 1

(b) x / 3 + X / 4 = 5
LCM 12
4x + 3x = 5 (12)
7x = 60
x = 60 / 7

(c) x / 3 + 7 = X / 2 + 5
x / 3 - x / 2 = 5 - 7
LCM 6
2x - 3x = - 12
- x = - 12
x = 12