Question

ln a triangle, angleA-B=33°, angleB-C=18°. Find the angles of a triangle.

Answer 1

Given that :-

A - B = 33...... (1)
B - C = 18........(2)

FROM EQUATION (1)

A = 33 + B ...... (3)

FROM EQUATION (2)

C = B - 18 ...... (4)


NOW,

ACCORDING TO ANGLE SUM PROPERTY OF A TRIANGLE :-

A + B + C = 180


FROM EQUATION (3) AND (4) REPLACING THE VALUES OF 'A' AND 'C'
SO,

33 + B + B + B - 18 = 180
OR,
3B + 15 = 180
OR,
3(B + 5) = 180
OR,
B + 5 = 180/3 = 60
OR,
B = 60 - 5 = 55



NOW,

FINDING OTHER ANGLES :-

A = 33 + B = 33+55 = 88

C = B - 18 = 55 - 18 = 37

SO,
THE ANGLES OF THE TRIANGLE ARE AS FOLLOWS :-
A = 88 DEGREES
B = 55 DEGREES
C = 37 DEGREES


Thanks!