Question

ln ∆ABC , the angle at AB is right , it's area is 48 square centimetres and the length of BC is 8 centimetres the side of BC is extended by 6 centimetres to D what is the area of ∆ADC
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Answer 1

Heyyy!!

Here Is Your Answer:-

A(ABD)-A(ABC)=A(ADC)

A(ABC)=1/2×BASE×HEIGHT

48=1/2×8×H

H=12=AB

A(ABD)=1/2×(6+8)×12

A(ABD)=84

THEREFORE

84-48=36CM^2

Answer 2

Given ∠B=90∘,AB=28cm,BC=21cm

Area of shaded region=ar△ABC+area of semicircle AC-ar quarter circle BC

=21×BC×AB+21×π(2AC)2−41×π(BC)2

=[21×21×28]+[21×722×41(282+212)2]−41×722×21×21

=294+[2811×1225]−346.5

=294+481.25−346.5=428.75㎠

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