Question

ln an A.P 4,10,16, then 10th terms is
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Answer 1

Answer:

d=10-4 =6 difference will remain constant in AP

1st term =4

2nd term =4+6 =10

3rd term = 10+6 =16

similarly

4th term =16+6 =22

Answer 2

Answer:

Step-by-step explanation:

first term = a = 4

common difference = d = 10-4 = 6

$n^{th} term = a + (n-1)d$

10th term = 4 + (10-1)6

                = 4 + (9)6

                = 4 + 54 = 58