Math, asked by abhinaykumar84897, 7 months ago

ln the figure given at right two of the angles are indicated .what are the measures of angle ACX and angle ACB?​

Answers

Answered by Anonymous
1

Answer:

AB=BC

In ΔABC, by Pythagoras theorem,

AC

2

=AB

2

+BC

2

AC

2

=AB

2

+AB

2

AC

2

=2AB

2

As ΔABE∼ΔACD is given, then it is known that the ratio of areas of equilateral triangles is equal to the ratio of the squares of their corresponding sides, so,

ar(ΔACD)

ar(ΔABE)

=

AC

2

AB

2

ar(ΔACD)

ar(ΔABE)

=

2AB

2

AB

2

ar(ΔACD)

ar(ΔABE)

=

2

1

Therefore, ar(ΔABE):ar(ΔACD)=1:2

Step-by-step explanation:

Hope This Will Help You Plz thanx My Ans

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