ln the given figure ABCD is the rectangle of dimensions 21 cm × 14 cm. A semicircle is drawn with BC as diameter . Find the area and the perimeter of the shaded region in the figure.
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22
Area of shaded region :
area of rectangle = l×b
>> 21×14= 294cm^2
Diameter of circle=14cm
radius=7cm
area of semi circle = πr^2/2
= 22/7 × 7×7 /2
= 77 ,cm^2
Area of shaded region:
294-77
217cm^2
area of rectangle = l×b
>> 21×14= 294cm^2
Diameter of circle=14cm
radius=7cm
area of semi circle = πr^2/2
= 22/7 × 7×7 /2
= 77 ,cm^2
Area of shaded region:
294-77
217cm^2
Answered by
9
Area Of Shaded Region = Area Of rectangles - area of semi circle.
Since BC=14cm is diameter of given semicircle.
Therefore, Radius of the given semicircle = 7 cm.
Area Of semicircle = πr²=22/7*7*7= 154 cm
Area Of rectangle = (21*14)cm = 294 cm²
Area Of shaded Region = (308-77)cm= 231 cm
Since BC=14cm is diameter of given semicircle.
Therefore, Radius of the given semicircle = 7 cm.
Area Of semicircle = πr²=22/7*7*7= 154 cm
Area Of rectangle = (21*14)cm = 294 cm²
Area Of shaded Region = (308-77)cm= 231 cm
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