Question

ln the PQR and PQSare equilateral triangles,then find the coordinates of R and S ?

Answer 1

Answer:

R = (0,√3a)

&

S = (0,-√3a)

Step-by-step explanation:

side of eq. ∆=2a

height of eq. ∆ =

$\frac{ \sqrt{3} }{2} \times side \\ = \frac{ \sqrt{3} }{2} \times 2a$

=√3a

.°. , abscissa of R & S=0(as the points lies on y-axis)

ordinate of R =√3a (as it is on the positive side )

ordinate of S = -√3a(as it is on the negative side )