Question

LO Cover LLR
1. If cost of 3 toys is rupees 33, find the cost of 10 such toys.​

Answer 1

cost of 3 toys = 33,

cost of 1 toy = 11

cost of 10 such toys = 10 *11= 110

Answer 2

Answer:

let the cost of toys be ₹'x'

From 1st condition

x+3y=33 _______1

10x+ y=0 _______2

multiply eqn 2 by 3

we get,

30x+3y=3 _____3

add eqn 1 &3

we get,

40x=36

x=36/40

x=9.0

9.0×10

=₹90

Logically if cost of 3 toys is 33₹ then cost of 1 toy will be 11₹

then cost of such 10 toys will be 110₹