Question

LO. Find Time when
(1) Principal = Rs. 6000, S.I. = Rs. 1052 and Rate = 8% p.a.
(ii) Principal = Rs. 4000, Amount = Rs. 5450 and Rate = 12% p.a.​

Answer 1

Answer:

SI=P×R×T

1052=6000×8×T

T=1052/6000×8

T=0.21years

Answer 2

1) Time = 2.19 year

2) Time = 3.02 year

Step-by-step explanation:

(1) Principal = Rs. 6000, S.I. = Rs. 1052 and Rate = 8% p.a.

We know that,

Simple Interest = ( Principal × Rate × Time ) / 100

1052 = ( 6000 × 8 × Time ) / 100

Time = ( 1052 × 100 ) / ( 6000 × 8 )

Time = 105200 / 48000

Time = 2.19

Time = 2.19 year

___________________________

2) Principal = Rs. 4000, Amount = Rs. 5450 and Rate = 12% p.a.

We know that,

Simple Interest = Amount - Principal

Simple Interest = 5450 - 4000

Simple Interest = 1450

Simple Interest = ₹1450

We know that,

Simple Interest = ( Principal × Rate × Time ) / 100

1450 = ( 4000 × 12 × Time ) / 100

Time = ( 1450 × 100 ) / ( 4000 × 12 )

Time = 145000 / 48000

Time = 3.02

Time = 3.02 year