Question

loane
100Y80
8000 M
runs
outside
A 5m wide path
rectangle Park of length 10om and som ba
area of the path
and around a
find the
length of the park including path =
breadth of the park incluching path=​

Answer 1

Answer:

A 5m wide path is running around a rectangular park of length 20m and breadth 10m

To Find :

find the area of the path

Solution:

Length of park = 20 m

Width of park = 10 m

A 5 m wide path is running around a rectangular park

Outer length =20+5+5=30 m

Outer breadth = 10+5+5=20 m

Area of path = Outer area - Inner area = (30 \times 20)-(20 \times 10)=400 sq.m.(30×20)−(20×10)=400sq.m.

Hence The area of path is 400 sq.m.

Answer 2

Step-by-step explanation:

ANSWER

REF.Image

Area of the path = Area of larger rectangle − Area of smaller rectangle.

smaller rectangle : l=93mb=80m

larger rectangle : 2.5m wide path rounds all around outside smaller rectangle

∴ length of larger rectangle = length of smaller rectangle + 2×2.5

=93+5=98m

Breadth of larger rectangle = Breadth of smaller rectangle +2×2.5

80+5=85m

Area of larger rectangle = 98×85m

2

Area of smaller rectangle = 93×80m

2

∴ Area of path = (98×85−93×80)m

2

=8330−7440m

2

=890m

2

∴ Area of path = 890m

2

solution