Question

locate √11 and-√11 on the number line​

Answer 1

Explanation:

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Answer 2

Answer:

Hi frnd hope my answer helps

Explanation:

First draw a number line with center O.Take a point P with

distance OP=11 unit.

Take another point Q with distance OQ=1 unit.

So PQ=OP+OQ=11+1=12

Take a point M where M is the midpoint of PQ.

Therefore PM=MQ= ½PQ=6

Draw an arc with center M from point Q and draw a line perpendicular to PQ from point O which cuts the arc at point T.

As PQ and MT are radius of same arc, so MT=MQ=6

OM=OP-PM=11-6=5

Now ΔMOT is a right angled triangle with <MOT=90°

By using Pythagoras Theorem,

MT ² = OM² + OT²

Þ OT² = MT ² - OM²

Þ OT² = 6² - 5²

Þ OT = √11

Now drawing an arc with center O from point T to PQ,we get point R where the arc intersects the line PQ.

Since OT and OR both are radii of same arc,

So OT=OR=√11

Therefore √11 is placed at point R on number line