Question

Locate √3 on number line

Answer 1

❤ HELLO MATE ❤  

YOUR ANSWER ✔️✔️

First draw a number line having points (at least) [0,3]. If we denote the point 0 as “O” and point 1 as “A” then OA will be equal to 1 unit. Then at point A draw a perpendicular of length AB=1 unit ( equal to the distance from 0 to 1 in the number line i.e. OA). And join the points O and A, so that OAB is a right angled triangle. Then by pythagoras theorem,

OB^2=OA^2+AB^2

=> OB=sqrt (1^2+1^2)

=>OB = root2

Now, again draw a perpendicular at point B of length BC= 1 unit and join the points O and C. Again by pythagoras theorem we get OC = root 3. Then by compus taking radius =OC, draw an arc so that it cuts the number line at D. Then the distance OD will be the square root of 3.

--------Follow Me------------

I HOPE IT HELPS THANK YOU

Answer 2

⦁First construct thr BD of unit length perpendicular to OB.

ㅤ

⦁Then apply the Pythagoras theorem $\rm{OD = \sqrt{(\sqrt{2})^{2} + 1^{2} = \sqrt{3}}}$

ㅤ

⦁We can locate $\rm{\sqrt{3}}$ on number line by using a compass.

ㅤ

⦁We know that, O is the center and radius OD. Now let's draw an arc which intersects the number line at the point Q.

ㅤ

⦁Therefore, now the point Q = $\rm{\sqrt{3}}$