locate √3 on number line.
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At first draw a 3cm line-AO. Then, to that line leave 1cm extra. Cut an arc both above and below. Make a semicircle from A to B. You will get the mid point of AB after joining the arcs. Make a perpendicular line from O till it touches the semicircle. Leave the pin of the compass on O and pencil on the point where the semicircle and the perpendicular has touched. And draw a arc. The point which you have got is root 3.
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AyushSingh9939:
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⦁First construct thr BD of unit length perpendicular to OB.
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⦁Then apply the Pythagoras theorem
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⦁We can locate on number line by using a compass.
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⦁We know that, O is the center and radius OD. Now let's draw an arc which intersects the number line at the point Q.
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⦁Therefore, now the point Q =
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