locate √3 on the number line
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To locate √3 on the number line, we need to: Build BD that passes via point OB perpendicular to it. Using Pythagora's theorem, we notice that OD = √ ((√2)^2+1^2) = √3. Draw an arc with centre O and radius OD to cut the number line at Q.
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◾Again by pythagoras theorem we get OC = root 3. Then by compus taking radius =OC, draw an arc so that it cuts the number line at D. Then the distance OD will be the square root of 3.
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