Locate √3
or the Number line
Answers
Step-by-step explanation:
First draw a number line having points (at least) [0,3]. If we denote the point 0 as “O” and point 1 as “A” then OA will be equal to 1 unit. Then at point A draw a perpendicular of length AB=1 unit ( equal to the distance from 0 to 1 in the number line i.e. OA). And join the points O and A, so that OAB is a right angled triangle. Then by pythagoras theorem,
OB^2=OA^2+AB^2
=> OB=sqrt (1^2+1^2)
=>OB = root2
Now, again draw a perpendicular at point B of length BC= 1 unit and join the points O and C. Again by pythagoras theorem we get OC = root 3. Then by compus taking radius =OC, draw an arc so that it cuts the number line at D. Then the distance OD will be the square root of 3.
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⦁First construct the BD of unit length perpendicular to OB.
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⦁Then apply the Pythagoras theorem
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⦁We can locate on number line by using a compass.
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⦁We know that, O is the center and radius OD. Now let's draw an arc which intersects the number line at the point Q.
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⦁Therefore, now the point Q =