locate √5, √10, √11, √13 on the number line.
Answers
Answer:
Presentation of 5 on number line:
We write 5 as the sum of the square of two natural numbers:
5=1+4=12+22
On the number line, take OA=2 units.
Draw BA=1 unit, perpendicular to OA. Join OB.
By Pythagoras theorem, OB=5
Using a compass with centre O and radius OB, draw an arc which intersects the number line at the point C. Then, C corresponds to 5.
Presentation of 10 on the number line:
We write 10 as the sun of the square of two natural numbers:
10=1+9=12+32
On the number line, taken OA=3 units.
Draw BA=1 unit, perpendicular to OA, Join OB.
By Phythagoras theorem, OB=10
Using a compass with centre O and radius OB, draw an arc which intersects the number line at the point C. Then, C corresponds to 10.
Presentation of 17 on the number line:
We write 17 as the sum of the square of two natural numbers.
17=1+16=12+42
On the number line, take OA=4 units.
Draw BA=1 units, perpendicular to OA. Join OB.
By Pythagoras theorem, OB=17
Using a compass with centre O and radius OB, draw an arc which intersects the number line at the point C.
Step-by-step explanation:
Then, C corresponds to 17.
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