Question

locate
$\sqrt{10 }$
on the number line

Answer 1

1. Draw a line, mark two points A and B where BA= 10 unit
2. Now draw BC = 1 unit
3. Now find the centre of line AC, mark it as 0.
4. Now take OC as radius and Drea an arc which make the meeting of A and C by arc.
5. From point B draw perpendicular BD which intersects arc at D .
6. Now take BD as radius and draw another arc DE which also meets once earlier drawn line.
Hence, you will have your √10 = BE =BD.