log [1 – {1 – (1 – x2)–1}–1]–1/2 can be written as
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Forget log and concentrate inside brackets. Start from innermost round bracket.
-1 power means reciprocal of the quantity
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[1 - {1 - (1 - x2 ) -1 }-1 ]-1/2
(1 - x2 ) -1 can be written as 1 / (1 - x2)
[1 - {1 - 1 / (1 - x2) }-1 ]-1/2
[1 - {(1 - x2 - 1) / (1 - x2) }-1 ]-1/2
[1 - {- x2 / (1 - x2) }-1 ]-1/2
[1 - {(1 - x2) / (-x2)} ]-1/2
[1 + {(1 - x2) / x2} ]-1/2
[(x2 + 1 - x2) / x2 ]-1/2
[1/x2 ]-1/2
[x2]1/2
√x2
x
-
So according to my solution, the answer should be logx
-1 power means reciprocal of the quantity
-
[1 - {1 - (1 - x2 ) -1 }-1 ]-1/2
(1 - x2 ) -1 can be written as 1 / (1 - x2)
[1 - {1 - 1 / (1 - x2) }-1 ]-1/2
[1 - {(1 - x2 - 1) / (1 - x2) }-1 ]-1/2
[1 - {- x2 / (1 - x2) }-1 ]-1/2
[1 - {(1 - x2) / (-x2)} ]-1/2
[1 + {(1 - x2) / x2} ]-1/2
[(x2 + 1 - x2) / x2 ]-1/2
[1/x2 ]-1/2
[x2]1/2
√x2
x
-
So according to my solution, the answer should be logx
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