A lot of 20 bulb contain 4 defective ones .one bulb is drawn at random from the lot.what is the probability that this bulb is defective,nondefective,
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20/4=5 is the answer
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***Probability of defective:- Total no. of bulbs=20
No. of defective bulbs=4
P(Of getting defective bulb)=No. of favourable outcomes/Total no. of outcomes
4/20=1/5
***Probability of getting non defective
No. of favourable outcome =20-4=16
P(Of getting non defective)=No. of favourable outcomes/Total no. of outcomes
=16/20
=4/5
hope it helps so
No. of defective bulbs=4
P(Of getting defective bulb)=No. of favourable outcomes/Total no. of outcomes
4/20=1/5
***Probability of getting non defective
No. of favourable outcome =20-4=16
P(Of getting non defective)=No. of favourable outcomes/Total no. of outcomes
=16/20
=4/5
hope it helps so
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