log(1)×log(1000) plzz do thiss
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Given,
= log(1) × log(1000)
= log(n)^0 × log(10)³
= 0 *logn × 3log(10)
= 0 × 3log(10)
= 0
Note:- log(mⁿ) = n×log(m)
2. Here n= any positive integer
= log(1) × log(1000)
= log(n)^0 × log(10)³
= 0 *logn × 3log(10)
= 0 × 3log(10)
= 0
Note:- log(mⁿ) = n×log(m)
2. Here n= any positive integer
hhhh33:
right answer
can I answer your question after some time
because I am busy
right now
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