log 128 base of 10 - log 625 base of 10
Answers
Answered by
3
Answer:
7log2 - 4log5 ≈ 2.1-2.79 ≈ -0.69
Step-by-step explanation:
Assuming log base 10 = log
log(128) - log(625) = 7log2 - 4log5
Answered by
1
Given : log₁₀128 - log₁₀625
To Find : Value
Solution:
log₁₀128 - log₁₀625
= log₁₀2⁷ - log₁₀5⁴
= 7 log₁₀2 - 4 log₁₀5
= 7 log₁₀2 - 4 log₁₀(10/2)
= 7 log₁₀2 - 4 (log₁₀10 - log₁₀2)
= 7 log₁₀2 - 4 log₁₀10 + 4log₁₀2)
= 11 log₁₀2 -4 (1)
= 11 log₁₀2 - 4
= 11(0.301) - 4 ( log₁₀2 =0.310)
= 3.311 - 4
= -0.689
log₁₀128 - log₁₀625 = -0.689
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