Question

Log 2=a, log 3=b, if 3^x+2=45. find x in a and b

Answer 1

2=a^e, 3=b^e
3^x+ 2=45
b^e^x +a^e =45..

Answer 2

Answer:(1-a)/b

Step-by-step explanation:

log 2=a      -(1)

log 3=b      -(2)

now, 3^x+2=45

= 3^x * 3^2=45

= 3^x * 9=45

=3^x=5

<<Remember that in all logs below the base is always 10 taken by me>>

<<Putting Log on both sides>>

=> log3^x = log5

= x*log3 = log5

=> x=log5/log3

or x= log5/b            <<log3=b (from2)>>

x= log(5*2/2)/b          <<Multiplying and dividing 5 by 2>>

x= log(10/2)/b

x = (log10 - log2)/b

x= (1-a)/b                  <<log 10 to the base 10 is 1>>&<<log2=a (from1)>>

Hence answered

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