Question

log 2 base 10 =0.3010 log 7 base 10=0.8450 then log 7 base √2​

Answer 1

Answer:

$log_{ \sqrt{2} }(7) = \frac{ log(7) }{ log( \sqrt{2} ) } \\ = \frac{ log(7) }{ \frac{1}{2} log(2) } \\ = 2 \times \frac{0.8450}{0.3010} \\ = 2 \times 2.8073 = 5.6146$

Answer 2

Answer:

this is correct................................