Question

log 2 base 16+ 3 log 2 base 2​

Answer 1

Answer:

????.............known doing

Explanation:

?????

Answer 2

Explanation:

Valueoflog216−log22

=log_{2}2^{4}-log_{2}2=log224−log22

=4log_{2}2 - log_{2}2=4log22−log22

____________________

We know the logarithmic laws:

\begin{gathered}i) log_{a}n^{m} = mlog_{a}n\\ii) log_{a}a = 1\end{gathered}i)loganm=mloganii)logaa=1

____________________

\begin{gathered}= 4-1\\=3\end{gathered}=4−1=3

Therefore,

Value \: of \: log_{2}16-log_{2}2 = 3Valueoflog216−log22=3

•••♪