Question

Log(225/32)-log(23/31)+log(64/729)

Answer 1

Hey user

Here is your answer : -

$log( \frac{225}{32} ) - log( \frac{23}{21} ) + log( \frac{64}{729} ) \\ \\ = log( \frac{225}{32} \div \frac{23}{21} \times \frac{64}{729} ) \\ \\ = log( \frac{225}{32} \times \frac{21}{23} \times \frac{64}{729} ) \\ \\ = log(0.56)$


Thank you .