Question

log 256/log 1024....

Answer 1

Solution:

______________________

we know the logarithmic laws:

i)n log m = log mⁿ

ii) $log_{x}x = 1$

_______________________

Now ,

log 256/log 1024

= ( log 2^8 )/(log 2^10)

= (8 log 2)/(10 log 2)

= 8/10

= 4/5

••••

Answer 2

Answer:

Step-by-step explanation:

For logarithmic equations,  

log

b

(

x

)

=

y

is equivalent to  

b

y

=

x

such that  

x

>

0

,  

b

>

0

, and  

b

≠

1

. In this case,  

b

=

1024

,  

x

=

256

, and  

y

=

4

5

.

b

=

1024

x

=

256

y

=

4

5

Substitute the values of  

b

,  

x

, and  

y

into the equation  

b

y

=

x

.

1024

4

5

=

256