Question

log 27÷ log 9 = ?

please answer me

Answer 1

hey there !!!

using logarithmic formula,

◆log a^b = b log a

so here in the given question.

=) log27 = log3^3

**using above formula **

=) log3^3 = 3log3 ----------(1)

similarly ,

=) log9 = log3^2 = 2log3 ------(2)

now , dividing equation 1 ans 2

=) log27 ÷ log9 =3lo3/2log3

cancel out log3 , we get

= 3/2 = 1.5 ans.

______________________________

Hope it will help u

Answer 2

Given : log 27  ÷ log 9

To Find :   Simplify

Solution:

log 27  ÷ log 9

27 = 3 x 3 x 3 = 3³

9 = 3 x 3 = 2²

= log ( 3³ ) ÷ log ( 3²)

log aⁿ =  n log a

log ( 3³ )  = 3 log 3

log ( 3²) = 2 log 3

=  3 log 3  ÷ 2 log 3

Cancelling  log 3 from numerator and denominator

= 3 ÷ 2

= 3/2

log 27  ÷ log 9  = 3/2 = 1.5

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