Log(2x+1) + log(3x-1) = 0, find x
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Answered by
17
Step-by-step explanation:
log(2x+1)+log(3x-1)=0
log(2x+1)(3x-1)=log1
(2x+1)(3x-1)=1
2x+1=1. or. 3x-1=1
x=0. or. x= -2/3
Answered by
2
Step-by-step explanation:
Step-by-step explanation: log(2x+1)+log(3x-1)=0 log(2x+1)(3x-1)=log1 (2x+1)(3x-1)=1 2x+1=1. or. 3x-1=1 x=0. or. x= -2/3
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