Question

log 36
9
(27)
plz solve this

Answer 1

log 36= 1.556302500767287
log 9= 0.59424350943
log 27= 1.43136376416
please mark as brain list please

Answer 2

 log36 you first have to write number 36 as a product of powers of 2 and 3.

36=6^2=(2⋅3)^2

So you can write:

log36=log(2⋅3)^2

Now you can use the properties of logarythms which say rhat:

logab = b⋅loga log(a⋅b) = loga+logb

After using rule 1 you get:

log(2⋅3)^2= 2⋅log(2⋅3)

Now if you use rule 2 you get the final result:

2⋅log(2⋅3)=2⋅(log2+log3)

log36=2⋅(log2+log3)
===============================
log 9

=log 3^2

=2 log 3

= .9542
===============================
log 27

=log 3^3

= 3 log 3

=1.431
===============================
Hope it's helpful