log 3x+4=log 729 then find the value of x
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6
log 3^x+4=log 729
log 3^x+4=log 3^6
removing log on either sides
x+4=6
x=6-4
x=2
log 3^x+4=log 3^6
removing log on either sides
x+4=6
x=6-4
x=2
Answered by
2
log 3 x+4 = log 729
log 3 x+4 = log 3 power 6
x+4 = 6 (as bases are same)
x = 6-4
x = 2
log 3 x+4 = log 3 power 6
x+4 = 6 (as bases are same)
x = 6-4
x = 2
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