log 5 + log 3 - log 2
Answers
Answered by
1
Answer:
log6+2log5+log4–log3–log2
=(log6+log5
2
+log4)–(log3+log2)
=log(6×5
2
×4)–log3×2
=log
3∗2
6×5
2
×4
=log(5
2
×4)
=log(25×4)=log100=2
Hence, log6+2log5+log4–log3–log2=2
Answered by
1
Answer:
log 5
+log 3
______
log 2
-log 2
______
log 0
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