log 5 to the base 10 = log 5 then 5=
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I cannot understand the question
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Step-by-step explanation:
log5 base 10 can be written as
log10/2 => log10-log2 (log a/b= loga-logb)
1-log2 =>1–0.301= 0.699
(log a base a=1)& (log2base10=0.301)
You must know the common log of certain number like log2= 0.301 and log3= 0.4771 to calculate common log of other numbers.
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