Question

log 7 1/49=log7 1/7power2

Answer 1

$log_{7}( \frac{1}{49} ) \\ \\ = log_{7}( \frac{1}{ {7}^{2} } )$

$= log_{7}( {7}^{ - 2} ) \\ \\ = - 2 \: log_{7}(7)$

$= - 2 \times 1 \\ \\ = - 2$