Math, asked by AmoghKhan7302, 11 months ago

Log a^2 /bc+Log b^2/ca+Log c^2/ab =0

Answers

Answered by ihrishi
5

Step-by-step explanation:

log( \frac{ {a}^{2} }{bc} ) + log( \frac{ {b}^{2} }{ac} ) + log( \frac{ {c}^{2} }{ab} )  = 0\\ LHS = log( \frac{ {a}^{2} }{bc} ) + log( \frac{ {b}^{2} }{ac} ) + log( \frac{ {c}^{2} }{ab} ) \\  = log \{ \frac{ {a}^{2} }{bc}  \times\frac { {b}^{2} }{ac} \times \frac{ {c}^{2} }{ab}  \} \\  = log \{ \frac{ {a}^{2} }{ {a}^{2}}  \times  \frac{ {b}^{2} }{ {b}^{2} }  \times  \frac{ {c}^{2} }{ {c}^{2} }  \}\\  = log \{1  \times  1 \times  1 \} \\  = log \: 1 \\  = 0 \\  = RHS \\ thus \: proved \\

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