Math, asked by rajashekarlucky, 8 months ago

log a 3=2, why 'a' is irrational? give reason​

Answers

Answered by harendrachoubay
8

'a' is irrational .

Step-by-step explanation:

We have,

\log_a 3 = 2

a is a irrational, give reason.

\log_a 3 = 2

By logarithm property,

a^{2} = 3

⇒ a = 3^{\dfrac{1}{2} }

⇒ a = \sqrt{3}

\sqrt{3} is an irrational number.

\sqrt{3} is an infinite, non-recurring decimal.

Using a calculator gives:

a =  \sqrt{3}  =  1.7320508 ... .

Thus, a is irrational .

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